/*
 * C program to accept a decimal number and convert it to binary
 * and count the number of 1's in the binary number
 */
#include <stdio.h>

void main()
{
    long num, decimal_num, remainder, base = 1, binary = 0, no_of_1s = 0;
    printf("Enter a decimal integer \n");
    scanf("%ld", &num);
    decimal_num = num;
    while (num > 0)
        {
            remainder = num % 2;
            /*  To count no.of 1s */
            if (remainder == 1)
                {
                    no_of_1s++;
                }
            binary = binary + remainder * base;
            num = num / 2;
            base = base * 10;
        }
    printf("Input number is = %d\n", decimal_num);
    printf("Its binary equivalent is = %ld\n", binary);
    printf("No.of 1's in the binary number is = %d\n", no_of_1s);
}